(12x^2+9x)/(3x)+(6x^3-3x^2)/x^2

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Solution for (12x^2+9x)/(3x)+(6x^3-3x^2)/x^2 equation: 


D( x )

3*x = 0

x^2 = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(12*x^2+9*x)/(3*x)+(6*x^3-(3*x^2))/(x^2) = 0

(12*x^2+9*x)/(3*x)+(6*x^3-3*x^2)/(x^2) = 0

(x^2*(12*x^2+9*x))/(3*x*x^2)+(3*x*(6*x^3-3*x^2))/(3*x*x^2) = 0

x^2*(12*x^2+9*x)+3*x*(6*x^3-3*x^2) = 0

30*x^4 = 0

(30*x^4)/(3*x*x^2) = 0

(30*x^4)/(3*x*x^2) = 0 // * 3*x*x^2

30*x^4 = 0

30*x^4 = 0 // : 30

x^4 = 0

x = 0

x in { 0} 

x belongs to the empty set

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